As shown in figure, masses of $4 k g$ and $5 k g$ are joined through a pulley. The table and pulley are frictionless. The magnitude of acceleration of $5 k g$ mass will be

49 m / s^{2}

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5.44 m / s^{2}

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19.5 m / s^{2}

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2.72 m / s^{2}

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Solution

The correct option is B $5.44 m / s^{2}$
Given,
$\begin{matrix} m_{1} = 5 k g m_{2} = 4 k g a = \frac{m_{1} g}{m_{1} + m_{2}} a = \frac{5 \times 9.8}{(9)} a = \frac{49}{9} a = 5.44 \frac{m}{s^{2}} \end{matrix}$
$∴$ Option $B$ is correct.

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As shown in figure, masses of 4 kg and 5 kg are joined through a pulley. The table and pulley are frictionless. The magnitude of acceleration of 5 kg mass will be

The correct option is B 5.44m/s2Given,m1=5kgm2=4kga=m1gm1+m2a=5×9.8(9)a=499a=5.44ms2∴ Option B is correct.

As shown in figure, masses of $4 k g$ and $5 k g$ are joined through a pulley. The table and pulley are frictionless. The magnitude of acceleration of $5 k g$ mass will be

The correct option is B $5.44 m / s^{2}$
Given,
$\begin{matrix} m_{1} = 5 k g m_{2} = 4 k g a = \frac{m_{1} g}{m_{1} + m_{2}} a = \frac{5 \times 9.8}{(9)} a = \frac{49}{9} a = 5.44 \frac{m}{s^{2}} \end{matrix}$
$∴$ Option $B$ is correct.