Question

As shown in figure, on bringing a chance Q from point A to B and from B to C, the work done are 2 joules and -3 joules respectively. The work done in bringing the charge from C to A will be:

• A. -1 joule
• B. 1 joule
• C. 2 joules
• D. 5 joules

Answer 1

The correct option is B 1 joule

As we know that electrostatic forms is conservative in nature, work done in moving an electric charge along a closed path $=0$

$W_{A-B}+W_{B-C}+W_{C-A}=0$ - $\left(1\right)$

Now, $W_{A-B}=2J$

$W_{B-C}=-3J$

putting in $\left(1\right)$

$2+(-3)+W_{C-A}=0$

$\Rightarrow W_{C-A}=1J$

Hence work done in moving charge $Q$ from $C$ to $A$ is $1$ Joule