As shown in figure, the tension in the horizontal cord is 30N. The weight w and tension in the string OA in newton are.
A
30√3,30
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B
30√3,60
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C
60√3,30
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D
None of the above
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Solution
The correct option is B30√3,60
Horizontal and vertical components of tension are shown in the figure. From the figure, Tsin30o=30 ...........(i) Tcos30o=w ..........(ii) By solving Eqs. (i) and (ii), we get w=30√3N and T=60N.