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Question

As shown in figure two masses 15kg each are suspended through two strings tied to a spring balance after passing over frictionless pulleys. The reading the balance will be:

281485_3504813deccc441888374acf320d681f.png

A
zero
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B
15kg
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C
30kg
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D
7.5kg
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Solution

The correct option is A 15kg
let the tension in the string be T
mgT=ma
system is at rest hence a=0
T=mg

let the extension in spring be x then Fx=kx
at the end of spring balance and acceleration is zero
FxT=0
F=T=mg that is 15kg.wt

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