As shown in figure, two masses of 3.0 kg and 1.0 kg are attached at the two ends of a spring having
force constant 300 N/m . The natural frequency of oscillation for the system will be hz.

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Solution

The correct option is A 3
The reduced mass of the system is $m^{'} = (3) (1) / (3 + 1) = 3 / 4 = 0.75$ and the force constant is k=300
Thus, frequency $f = (1 / 2 π) \sqrt{(} 300 / 0.75) = 10 / π = 3$ Hz
The correct answer is (a)

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As shown in figure, two masses of 3.0 kg and 1.0 kg are attached at the two ends of a spring havingforce constant 300 N/m . The natural frequency of oscillation for the system will be hz.

The correct option is A 3The reduced mass of the system is m′=(3)(1)/(3+1)=3/4=0.75 and the force constant is k=300Thus, frequency f=(1/2π)√(300/0.75)=10/π=3 HzThe correct answer is (a)

As shown in figure, two masses of 3.0 kg and 1.0 kg are attached at the two ends of a spring having
force constant 300 N/m . The natural frequency of oscillation for the system will be hz.

The correct option is A 3
The reduced mass of the system is $m^{'} = (3) (1) / (3 + 1) = 3 / 4 = 0.75$ and the force constant is k=300
Thus, frequency $f = (1 / 2 π) \sqrt{(} 300 / 0.75) = 10 / π = 3$ Hz
The correct answer is (a)