Question

As shown in the above figure, $\angle A$ of pentagon ABCDE, measures ${50}^{\circ }$. Find the total measure of the other 4 interior angles.

• A. ${130}^{\circ }$
• B. ${200}^{\circ }$
• C. ${310}^{\circ }$
• D. ${432}^{\circ }$
• E. ${490}^{\circ }$

Answer 1

Answer: (E)

${490}^{\circ }$

Sum of interior angle of pentagon is $(n-2)180={540}^{\circ }$ (for pentagon n=5)

$\angle A+4$interior angle $=$ ${540}^{\circ }$

$4$ interior angle $=$ ${540}^{\circ }-\angle A$

$4$ interior angles $=$ ${540}^{\circ }-{50}^{\circ }$

$4$ interior angle $={490}^{\circ }$