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Standard XII

Physics

Projectile from a Height

As shown in t...

Question

As shown in the figure a projectile is fired with a horizontal velocity of $330 m/s$ from the top of a cliff $80 m$ high. How far from the foot of the cliff will it strike?

660 m

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1320 m

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330 m

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2640 m

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Solution

The correct option is B $1320 m$
Time taken by the projectile to reach ground
$T = \sqrt{\frac{2 H}{g}} = \sqrt{\frac{2 \times 80}{10}}$
$T = 4 s$
Horizontal distance covered by the projectile
$x = u_{x} \times T$ where $u_{x}$ is the horizontal velocity of projection.
$x = 330 \times 4 = 1320 m$

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As shown in the figure a projectile is fired with a horizontal velocity of 330 m/s from the top of a cliff 80 m high. How far from the foot of the cliff will it strike?

The correct option is B 1320 mTime taken by the projectile to reach ground T=√2Hg=√2×8010 T=4 s Horizontal distance covered by the projectile x=ux×T where ux is the horizontal velocity of projection. x=330×4=1320 m

As shown in the figure a projectile is fired with a horizontal velocity of $330 m/s$ from the top of a cliff $80 m$ high. How far from the foot of the cliff will it strike?

The correct option is B $1320 m$
Time taken by the projectile to reach ground
$T = \sqrt{\frac{2 H}{g}} = \sqrt{\frac{2 \times 80}{10}}$
$T = 4 s$
Horizontal distance covered by the projectile
$x = u_{x} \times T$ where $u_{x}$ is the horizontal velocity of projection.
$x = 330 \times 4 = 1320 m$