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Chord

As shown in t...

Question

As shown in the figure above, O is the centre and OA and OB are the radii of the circle of 10 units each. Calculate the length of minor arc AB , if $∠ A O B = \frac{2 π}{5}$ .

π

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2 π

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4 π

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20 π

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Solution

The correct option is C $4 π$
Given radius of circle is 10 and angle AOB= $\frac{2 π}{5}$
We know that radian measure of central angle = $\frac{l e n g t h o f a r c}{r e d i u s}$
$∴ \frac{2 π}{5} = \frac{a r c l e n g t h A B}{10}$
$\Rightarrow a r c l e n g t h A B = \frac{20 π}{5} = 4 π$

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As shown in the figure above, O is the centre and OA and OB are the radii of the circle of 10 units each. Calculate the length of minor arc AB , if ∠AOB=2π5.

The correct option is C 4πGiven radius of circle is 10 and angle AOB=2π5We know that radian measure of central angle =length of arcredius∴2π5=arc length AB10⇒arc length AB=20π5=4π

As shown in the figure above, O is the centre and OA and OB are the radii of the circle of 10 units each. Calculate the length of minor arc AB , if $∠ A O B = \frac{2 π}{5}$ .

The correct option is C $4 π$
Given radius of circle is 10 and angle AOB= $\frac{2 π}{5}$
We know that radian measure of central angle = $\frac{l e n g t h o f a r c}{r e d i u s}$
$∴ \frac{2 π}{5} = \frac{a r c l e n g t h A B}{10}$
$\Rightarrow a r c l e n g t h A B = \frac{20 π}{5} = 4 π$