Question

As shown in the figure at 200 K and 500 atm value of compressibility factor is 2 (approx). Then the volume of the gas at this point will be:

• A. $0.01$ L
• B. $0.09$ L
• C. $0.065$ L
• D. $0.657$ L

Answer 1

Answer: (C)

$0.065$ L

The expression for the compressibility factor is $z=\frac{P{V}_m}{RT}$.

On rearranging the above, expression, $V_m=\frac{z.RT}{P}$.

Substitute values in the above expression:

$V_m=\frac{2\times 0.082\times 200}{500}=0.065L$.

Thus the volume of the gas is $0.065L$.