As temperature is raised from $20^{\circ} C$ to $40^{\circ} C$ , the average kinetic energy of neon atoms changes by a factor of which of the following?

1 / 2

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2

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313 / 293

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\sqrt{313 / 293}

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Solution

The correct option is C $313 / 293$
$T_{1} = 20 + 273 = 293 K$
$T_{2} = 40 + 273 = 313 K$
$¯ ¯¯¯¯¯¯¯¯¯ ¯ K . E = \frac{3}{2} k T$
At $293 K$
${¯ ¯¯¯¯¯¯¯¯¯ ¯ K . E}_{1} = \frac{3}{2} k \times 293$
At $313 K$
${¯ ¯¯¯¯¯¯¯¯¯ ¯ K . E}_{2} = \frac{3}{2} k \times 313$
$\frac{{¯ ¯¯¯¯¯¯¯¯¯ ¯ K . E}_{2}}{{¯ ¯¯¯¯¯¯¯¯¯ ¯ K . E}_{1}} = \frac{313}{273}$

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As temperature is raised from 20∘C to 40∘C, the average kinetic energy of neon atoms changes by a factor of which of the following?

The correct option is C 313/293T1=20+273=293 K T2=40+273=313 K ¯¯¯¯¯¯¯¯¯¯¯K.E=32kT At 293 K ¯¯¯¯¯¯¯¯¯¯¯K.E1=32k×293 At 313 K ¯¯¯¯¯¯¯¯¯¯¯K.E2=32k×313 ¯¯¯¯¯¯¯¯¯¯¯K.E2¯¯¯¯¯¯¯¯¯¯¯K.E1=313273

As temperature is raised from $20^{\circ} C$ to $40^{\circ} C$ , the average kinetic energy of neon atoms changes by a factor of which of the following?