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Introduction to Electrophilic Substitution

As the initia...

Question

As the initial concentration increases from $0.75$ to $1.55 M$ in a reaction, $t_{1 / 2}$ decreases from $60$ to $29 s$ . The order of the reaction is:

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Solution

The correct option is C Second
We know that, half life of a reaction is given as:
$t_{1 / 2} \propto [A_{0}]^{1 - n}$
$\Rightarrow \frac{29}{60} = {(\frac{1.55}{0.75})}^{1 - n}$
$\Rightarrow n \approx 2$

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As the initial concentration increases from 0.75 to 1.55 M in a reaction,t1/2 decreases from 60 to 29 s. The order of the reaction is:

The correct option is C SecondWe know that, half life of a reaction is given as: t1/2∝[A0]1−n ⇒2960=(1.550.75)1−n ⇒n≈2

As the initial concentration increases from $0.75$ to $1.55 M$ in a reaction, $t_{1 / 2}$ decreases from $60$ to $29 s$ . The order of the reaction is:

The correct option is C Second
We know that, half life of a reaction is given as:
$t_{1 / 2} \propto [A_{0}]^{1 - n}$
$\Rightarrow \frac{29}{60} = {(\frac{1.55}{0.75})}^{1 - n}$
$\Rightarrow n \approx 2$