Question

As the s-character of hybridized orbital decreases, the bond angle also decreases.

• A. Decreases
• B. Increases

Answer 1

The correct option is A

Decreases

As the s-character of hybridized orbitals decreases the bond angle also decreases.
In $s{p}^3$ hybridisation: s-character $\frac{1}{4}$, bond angle ${109}^o$
In $s{p}^2$ hybridisation: s-character $\frac{1}{3}$, bond angle ${120}^o$
In sp hybridisation: s-character $\frac{1}{2}$, bond angle ${180}^o$