As the s-character of hybridized orbital decreases, the bond angle

Decreases

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Increases

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Does not change

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become zero

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Solution

The correct option is A Decreases
$A / C$ to bent's rule more electronegative occupy the position where S character is less and less $E N$ atom occupy the position of more $S -$ character $.$

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As $% s$ - character of a hybrid orbital increases

s

C - C

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