As the switch S is closed in the circuit shown in figure, current passed through it is:

5.0A

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6.0 A

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3.0 A

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Zero

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Solution

The correct option is A 5.0A
applying ohms law
$V_{1} = I_{1} R_{1} ⟹ I_{1} = \frac{V_{1}}{R_{1}} = \frac{10}{4} = 2.5 A$

$V_{2} = I_{2} R_{2} ⟹ I_{2} = \frac{V_{2}}{R_{2}} = \frac{5}{2} = 2.5 A$

$g r o u n d_{V} = 0 ⟹ I = 2.5 + 2.5 = 5 A$

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As the switch $S$ is closed in the circuit as shown in figure, current passed through it is

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