Question

As the switch S is closed in the circuit shown in figure, current passing through it is

• A. $4.5A$
• B. $6.0A$
• C. $3.0A$
• D. $Zero$

Answer 1

The correct option is C $3.0A$

Let Node voltage of $2\Omega$ is $V$

Applying KCL at $2\Omega$

$\frac{20-V}{4}=\frac{V}{2}+\frac{V-5}{4}\frac{20-V}{4}=\frac{2V+V-5}{4}20-V=3V-54V=25V=\frac{25}{4}=6.25V$

Now

$I=\frac{V}{R}=\frac{6.25}{2}=3.13A$

Option C is correct option.