As the temperature is raised from $20^{\circ}$ C to $40^{\circ} C$ , the average kinetic energy of neon atoms changes by a factor of which of the following?

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Solution

The correct option is C

$T_{1}$ = $273 + 20$ = $293 K$ and $T_{2}$ = $273 + 40$ = $313 K$ . As the kinetic energy is proportional to the temperature, we have

$\frac{E_{1}}{E_{2}} = \frac{T_{2}}{T_{1}} = \frac{293}{313} \Rightarrow \frac{E_{1}}{E_{2}} = \frac{313}{293}$

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As the temperature is raised from 20∘C to 40∘C, the average kinetic energy of neon atoms changes by a factor of which of the following?

The correct option is C T1 = 273 + 20 = 293K and T2 = 273 + 40 = 313K. As the kinetic energy is proportional to the temperature, we have E1E2 = T2T1 = 293313 ⇒ E1E2 = 313293

As the temperature is raised from $20^{\circ}$ C to $40^{\circ} C$ , the average kinetic energy of neon atoms changes by a factor of which of the following?

The correct option is C

$T_{1}$ = $273 + 20$ = $293 K$ and $T_{2}$ = $273 + 40$ = $313 K$ . As the kinetic energy is proportional to the temperature, we have

$\frac{E_{1}}{E_{2}} = \frac{T_{2}}{T_{1}} = \frac{293}{313} \Rightarrow \frac{E_{1}}{E_{2}} = \frac{313}{293}$