As the temperature is raised from $20^{o}$ C to $40^{o}$ C, the average kinetic energy of neon atoms changes by a factor of which of the following?

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Solution

We know,
$K E = \frac{3}{2} R T$
So,
$E_{1} = \frac{3}{2} \times R \times 293$
$E_{2} = \frac{3}{2} \times R \times 313$
So,
$E_{2} = \frac{313}{293} E_{1}$

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As the temperature is raised from 20oC to 40oC, the average kinetic energy of neon atoms changes by a factor of which of the following?

We know,KE=32RTSo,E1=32×R×293E2=32×R×313So,E2=313293E1

As the temperature is raised from $20^{o}$ C to $40^{o}$ C, the average kinetic energy of neon atoms changes by a factor of which of the following?

We know,
$K E = \frac{3}{2} R T$
So,
$E_{1} = \frac{3}{2} \times R \times 293$
$E_{2} = \frac{3}{2} \times R \times 313$
So,
$E_{2} = \frac{313}{293} E_{1}$