As we know, a code of three nitrogen bases is responsible for specifying one amino acid. In an ideal case, how many nitrogen bases would be present on a messenger RNA that transcribes a polypeptide containing 57 amino acids?

174

No worries! We‘ve got your back. Try BYJU‘S free classes today!

168

No worries! We‘ve got your back. Try BYJU‘S free classes today!

171

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 171
One codon coding for one amino acid contains three nitrogen bases. There are 57 nitrogen bases in the sequence of the mRNA. So the number of the nitrogen bases which are required for the production of the 57 amino acids are 57 x 3 = 171 nitrogen bases.
Thus, the correct answer is option A.

Suggest Corrections

Similar questions

Q. Suppose a complete polypeptide chain contains

100

amino acid molecules.How many nitrogen bases will be involved in the genetic code on the m-RNA for the formation and release of such a polypeptide chain ?

Q. How many bases in mRNA (only sense codon) would be present for a polypeptide chain of 80 amino acids?

Q. A sequence of how many nucleotides in messenger RNA makes a codon for an amino acid?

Q. Choose the correct answer from the alternatives given :
Read the following statements.
(i) One codon codes for only one amino acid.
(ii) Some amino acids are coded by more than one codon.
(iii) The, sequence of triplet nitrogenous bases in DNA or mRNA corresponds to the amino acid sequence in the polypeptide chain.
Give suitable terms for the characteristics of genetic code as per the above statements.

If there are 999 bases in an RNA that code for a protein with 333 amino acids, and the base at position 901 is deleted such that the coding length of the RNA becomes 998 bases, how many codons will be altered?

Join BYJU'S Learning Program