Ashin invested an amount of ₹13,900 divided into two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years is ₹3508, then what was the amount invested in Scheme B (in rupees)?
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Solution
Let the sum invested in Scheme A be ₹x and that in Scheme B be ₹(13900 - x).
Then
14×x×2100+(13900−x)×11×2100=3508
28x - 22x = 350800 - (13900 × 22)
6x = 45000
x = 7500
So, sum invested in Scheme B = ₹(13900 - 7500) = ₹6400