Ashok got the following marks in different subjects in a unit test, $20, 11, 21, 25, 23$ and $14$ . What is arithmetic mean of his marks?

Open in App

Solution

$M e a n = \frac{\sum x}{n},$ where $n = n o . n = 6$ $o f$ $u n i t$ $t e x t .$
$∴ \sum x = 114$
$∴$ $A r i t h m e t i c$ $m e a n = \frac{114}{6} = 19$ $M a r k s$

Suggest Corrections

Similar questions

Ram appeared in his mid-term examination and his marks in different subjects were:-

$\begin{matrix} Subject & Marks Science & 75 Maths & 85 Hindi & 75 English & 75 Social Science & 65 \end{matrix}$

Find the mean of this distribution of marks.

Q. In a class test, the sum of the marks obtained by P in Mathematics and science is 28. Had he got 3 marks more in mathematics and 4 marks less in Science. The product of his marks would have been 180. Find his marks in two subjects.

Q. In a class test, Dinesh got 12 marks out of 20 in science and 20 marks out of 30 in maths. In which subject his performance is better?

Q. In a class test, the sum of Arun's marks in Hindi and English is 30. Had he got 2 marks in Hindi and 3 marks less in English, the product of the marks would have been 210. Find his marks in the two subjects.

In a class test, the sum of Kamal's marks in mathematics and English is 40. Had he got 3 marks more in mathematics and 4 marks less in English, the product of the marks would have been 360. Find his marks in two subjects separately.

Join BYJU'S Learning Program

Ashok got the following marks in different subjects in a unit test, 20,11,21,25,23 and 14. What is arithmetic mean of his marks?

Mean=∑xn, where n=no.n=6 of unit text.∴∑x=114∴ Arithmetic mean=1146=19 Marks

Ashok got the following marks in different subjects in a unit test, $20, 11, 21, 25, 23$ and $14$ . What is arithmetic mean of his marks?

$M e a n = \frac{\sum x}{n},$ where $n = n o . n = 6$ $o f$ $u n i t$ $t e x t .$
$∴ \sum x = 114$
$∴$ $A r i t h m e t i c$ $m e a n = \frac{114}{6} = 19$ $M a r k s$