Ashok left from place A (towards place B) at 8 am and Rahul left from place B (towards place A) at 10 am. The distance between place A and place B is 637 km. If Ashok and Rahul are travelling at a uniform speed of 39 km/h and 47 km/h respectively, at what time will they meet?

5 : 30 pm

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4 : 30 pm

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5 : 00 pm

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4 : 00 pm

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3 : 30 pm

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Solution

The correct option is B 4 : 30 pm

$T i m e t a k e n = \frac{T o t a l d i s t a n c e t o c o v e r}{R e l a t i v e v e l o c i t y} = \frac{559}{86} = 6.5 h$
$∴$ Meeting time
= 10 am + 6.5 h = 4 : 30pm

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