Aspirin has the formula $C_{9} H_{8} O_{4}$ . Number of moles of aspirin in a tablet weighing $500$ mg is $x \times 10^{- 5}$ . Then, the value of $x$ is ________.

Open in App

Solution

Molar mass of aspirin $= 180$ .

So, moles of aspirin $= \frac{500 \times 10^{- 3}}{180} = 2.78 \times 10^{- 3} = 278 \times 10^{- 5}$ mol.

Hence $x$ = 278

Suggest Corrections

Similar questions

Q. If 1 grain is equal to 642 mg, how many moles of aspirin (mot wt. = 169 ) are present in a 5 grain aspirin tablet?

Calculate the mass percentage of aspirin (C₉H₈O₄) in acetonitrile (CH₃CN) when 6.5 g of C₉H₈O₄ is dissolved in 450 g of CH₃CN.

Question 2.28

Calculate the mass percentage of aspirin $(C_{9} H_{8} O_{4})$ in acetonitrile $(C H_{3} C N)$ when 6.5g of $C_{9} H_{8} O_{4}$ is dissolved in 450 g of $C H_{3} C N$

Q. How many molecules of aspirin (Molar mass =

180 g/mol

) are present in

50 mg

of the tablet?

Q. One aspirin pill contains 360 mg of aspirin. To form 10 pills of aspirin from salicylic acid and acetic anhydride, how many grams of salicylic acid is required?

Join BYJU'S Learning Program

Aspirin has the formula C9H8O4. Number of moles of aspirin in a tablet weighing 500 mg is x×10−5. Then, the value of x is ________.

Molar mass of aspirin =180.So, moles of aspirin =500×10−3180=2.78×10−3=278×10−5 mol.Hence x = 278

Aspirin has the formula $C_{9} H_{8} O_{4}$ . Number of moles of aspirin in a tablet weighing $500$ mg is $x \times 10^{- 5}$ . Then, the value of $x$ is ________.

Molar mass of aspirin $= 180$ .

So, moles of aspirin $= \frac{500 \times 10^{- 3}}{180} = 2.78 \times 10^{- 3} = 278 \times 10^{- 5}$ mol.

Hence $x$ = 278