Assem went to a stationary shop and purchased $3$ pens and $5$ pencils for $R s .40$ . His cousin Manik bought $4$ pencils and $5$ pens for $R s . 58$ . If cost of $1$ pen is $R s . x$ , then which of the following represents the situation algebraically?

3 x + 5 y = 40

4 x + 5 y = 58

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3 x + 4 y = 40

5 x + 5 y = 58

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3 x + 5 y = 40

5 x + 4 y = 58

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3 x + 5 y = 40

4 x + 3 y = 58

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Solution

The correct option is C $3 x + 5 y = 40$ , $5 x + 4 y = 58$
Let the cost price of one pen $= x$
Let the cost price of one pencil $= y$
According to the problem,
Aseem's total cost price $= 3 x + 5 y = 40$ ....(1)
Manik's total cost price $= 5 x + 4 y = 58$ .....(2)

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Assem went to a stationary shop and purchased 3 pens and 5 pencils for Rs.40. His cousin Manik bought 4 pencils and 5 pens for Rs.58. If cost of 1 pen is Rs.x, then which of the following represents the situation algebraically?

The correct option is C 3x+5y=40, 5x+4y=58Let the cost price of one pen =xLet the cost price of one pencil=yAccording to the problem, Aseem's total cost price =3x+5y=40 ....(1)Manik's total cost price =5x+4y=58 .....(2)

Assem went to a stationary shop and purchased $3$ pens and $5$ pencils for $R s .40$ . His cousin Manik bought $4$ pencils and $5$ pens for $R s . 58$ . If cost of $1$ pen is $R s . x$ , then which of the following represents the situation algebraically?

The correct option is C $3 x + 5 y = 40$ , $5 x + 4 y = 58$
Let the cost price of one pen $= x$
Let the cost price of one pencil $= y$
According to the problem,
Aseem's total cost price $= 3 x + 5 y = 40$ ....(1)
Manik's total cost price $= 5 x + 4 y = 58$ .....(2)