Assertion : $44 g$ of $C O_{2}$ , $28$ g of $C O$ have same volume at STP. Reason: Both $C O_{2}$ and $C O$ are formed by $C$ and $O_{2}$ .

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is correct but Reason is incorrect

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Assertion is incorrect but Reason is correct

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Solution

The correct option is B Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
The molar masses of $C O_{2}$ and $C O$ are 44 g/mol and 28 g/mol respectively.

$44 g$ of $C O_{2}$ , $28$ g of $C O$ corresponds to 1 mole of each. Hence, they have the same volume at STP.

Both $C O_{2}$ and $C O$ are formed by $C$ and $O_{2}$ .

$C + O_{2} \to C O_{2}$

$2 C + O_{2} \to 2 C O$

Hence, both Assertion and Reason are correct but Reason is not the correct explanation for Assertion.

Hence, the correct option is $B$

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