Assertion :8 grams of methane occupies 11.2 litres of volume at 273 $K$ and 1 $a t m$ pressure. Reason: One mole of any gas at $S T P$ occupies 22.4 litres of volume.

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is correct but Reason is incorrect

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Assertion is incorrect but Reason is correct

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Solution

The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
At STP conditions, one mole of gas occupies $22.4$ liters of volume.

Here, $8 g$ of methane means only half mole. For one mole, $22.4$ liters they will occupy. For half mole, only $11.2$ liters they will occupy.

$m o l e v o l 1 ⟶ 22.4 \frac{1}{2} ⟶ (x)$
$x = \frac{1}{2} \times \frac{22.4}{1} = 11.2$ liters.

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Assertion :8 grams of methane occupies 11.2 litres of volume at 273 K and 1 atm pressure. Reason: One mole of any gas at STP occupies 22.4 litres of volume.

Assertion :8 grams of methane occupies 11.2 litres of volume at 273 $K$ and 1 $a t m$ pressure. Reason: One mole of any gas at $S T P$ occupies 22.4 litres of volume.