Question

Assertion A: $(3,2)$ lies above the line $x+y+1=0$
Reason R: If the point $P(x_1,y_1)$ lies above the line $L=ax+by+c$, then $L(x_1,y_1)>0$

• A. A and R are true and R is the correct explaination of A
• B. A and R are true and R not is the correct explaination of A
• C. A is true R is False
• D. A is False R is True

Answer 1

The correct option is A A and R are true and R is the correct explaination of A

$x+y+1=0$
Here $a,b,c>0$
Therefore if $L(x,y{)}_{3,2}>0,$ then it is sufficient to prove that it lies above the line.
Therefore
$x+y+1{|}_{3,2}$

$=3+2+1$
$=6$

Thus,

$x+y+1{|}_{3,2}>0$

Hence, the point $(3,2)$ lies above the line.