Question

Assertion$\left(A\right)$ : A point charge $q$ is placed near an arbitrary shaped solid conductor, as shown in the figure. The potential difference between points $\text{A}$ and $\text{B}$ within the conductor remains same irrespective of the magnitude of the charge $q.$

Reason$\left(R\right)$ : Electric field inside the solid conductor is zero under the electrostatic conditions.



Select the most appropriate answer from the options given below

• A. Both $A$ and $R$ are true and $R$ is the correct explanation of $A$
• B. Both $A$ and $R$ are true but $R$ is not the correct explanation of $A$
• C. $A$ is true but $R$ is false
• D. $A$ is false and $R$ is also false

Answer 1

The correct option is A Both $A$ and $R$ are true and $R$ is the correct explanation of $A$

Under electrostatic condition, Electric field inside the solid conductor is zero.

As we know, $E=-\frac{\Delta V}{\Delta x}$

If $E=0\Rightarrow V=\text{constant}$

Hence, point <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> $\text{A}$ and $\text{B}$ will have same potential i.e., $V_A-V_B=0$

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, $\left(A\right)$ is the correct answer.