Question

Assertion (A): Chlorine gas disproportionates in hot and conc. $NaOH$ solution.
Reason (R): NaCl and NaOCl are formed in the above reaction.

• A. Both (A) and (R) are true and (R) is the correct explanation of (A).
• B. Both (A) and (R) are true but (R) is not correct explanation of (A).
• C. (A) is true but (R) is false.
• D. (A) is false and (R) is true.

Answer 1

Answer: (C)

(A) is true but (R) is false.

The reaction of $Cl$ with hot and conc. $NaOH$ is as follows:
$3C{l}_2+6NaOH\to 5NaCl+NaCl{O}_3+3H_{2}O$
The oxidation state of chlorine is zero in reactant and in product it is -1 and +5 respectively. So it is disproportionation reaction.
The product are $NaCl$ and $NaCl{O}_3$. Hence (R) is wrong.