Assertion :A conducting equilateral loop $a b c$ is moved translationally with constant speed $v$ in uniform inward magnetic field $B$ as shown. Then: $V_{a} - V_{b} = V_{b} - V_{c}$ . Reason: Point $a$ is at higher potential than point $b$ .

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is correct but Reason is incorrect

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Assertion is incorrect but Reason is correct

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Solution

The correct option is D Assertion is incorrect but Reason is correct
Potential difference across the side ab= $B v l c o s 60^{\circ} = \frac{1}{2} B v l$
Potential difference across the side bc= $B v l$
Thus $V_{a} - V_{b} \neq V_{b} - V_{c}$
Consider forces acting on positive charges along the side ab. Force= $q (\to v \times \to B)$
Thus the positive charges tend to move towards the side a. Similarly negative charges tend to move towards the side b. Thus a is at higher potential than b

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Assertion :A conducting equilateral loop abc is moved translationally with constant speed v in uniform inward magnetic field B as shown. Then:Va−Vb=Vb−Vc. Reason: Point a is at higher potential than point b.

Assertion :A conducting equilateral loop $a b c$ is moved translationally with constant speed $v$ in uniform inward magnetic field $B$ as shown. Then: $V_{a} - V_{b} = V_{b} - V_{c}$ . Reason: Point $a$ is at higher potential than point $b$ .