Assertion (A) cos−1x≥sin−1x,∀x∈[−1,1] Reason (R) cos−1x is decreasing function ∀x∈[−1,1]
A
Both A and R are true and R is the correct explanation of A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Both A and R are true and R is not correct explanation of A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
A is true but R is false
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
A is false but R is true
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D A is false but R is true As we can see from the graph, cos−1(x) is a decreasing function while sin−1(x) is an increasing function on [−1,1] and sin−1(x)=cos−1(x) at x=1√2 Hence cos−1x≥sin−1(x) on [−1,1] is false.