Assertion :A deuteron and an a-particle are placed in an electric field. If $F_{1}$ and $F_{2}$ be the forces acting on them and $a_{1}$ and $a_{2}$ be their accelerations respectively then, $a_{1} = a_{2}$ . Reason: Forces will be same in electric field.

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is correct but Reason is incorrect

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Assertion is incorrect but Reason is correct

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Solution

The correct option is C Assertion is correct but Reason is incorrect
$q_{d} = e, m_{d} = 2 m_{p} = 2 m$
$q_{α} = 2 e, m_{α} = 4 m_{p} = 4 m$
$F_{1} = F_{d} = e E, F_{2} = F_{α} = 2 e E \neq F_{1}$
Further, $a_{1} = \frac{F_{1}}{2 m} = \frac{e E}{2 m}$
and $a_{2} = \frac{F_{2}}{2 m} = \frac{2 e E}{4 m} = \frac{e E}{2 m} = a_{1}$

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Assertion :A deuteron and an a-particle are placed in an electric field. If F1 and F2 be the forces acting on them and a1 and a2 be their accelerations respectively then, a1=a2. Reason: Forces will be same in electric field.

The correct option is C Assertion is correct but Reason is incorrectqd=e,md=2mp=2mqα=2e,mα=4mp=4mF1=Fd=eE,F2=Fα=2eE≠F1Further, a1=F12m=eE2mand a2=F22m=2eE4m=eE2m=a1

Assertion :A deuteron and an a-particle are placed in an electric field. If $F_{1}$ and $F_{2}$ be the forces acting on them and $a_{1}$ and $a_{2}$ be their accelerations respectively then, $a_{1} = a_{2}$ . Reason: Forces will be same in electric field.