Question

Assertion (A): $H_{2}S$ is more volatile than $H_{2}O$.
Reason (R): Oxygen atom is smaller in size as compared to sulphur.

• A. Both $A$ and $R$ are true and $R$ is the correct explanation of $A$
• B. Both $A$ and $R$ are true and $R$ is not the correct explanation of $A$
• C. $A$ is true but $R$ is false
• D. $A$ is false but $R$ is true

Answer 1

The correct option is B Both $A$ and $R$ are true and $R$ is not the correct explanation of $A$

Assertion:

$H_{2}O$ has hydrogen bonding interactions and hence, it exists as a liquid in room temperature. Due this hydrogen bonding interactions, its volatility decreases as boiling point increases. However, $H_{2}S$t has no hydrogen bonding because sulphur is less electronegative than oxygen.

Hence, $H_{2}S$ is more volatile than $H_{2}O$.

Reason:

Oxygen atom is smaller in size compared to sulphur which is true but this is not the correct explanation of A.

Hence, both A and R are true and R is not the correct explanation of A.