Assertion :(A): If A>0 & B>0,A+B=π6, then the maximum value of tanAtanB is 7−4√2 Reason: (R): If x1+x2+x3+.......xn=λ(constant), then value of x1,x2,x3,.......xn is greatest when x1=x2=x3=.......xn
A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Assertion is correct but Reason is incorrect
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Both Assertion flase but Reason is true
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
Assertion:
A+B=π6
tan(A+B)=tanπ6
tanA+tanB1−tanAtanB=1√3
1−tanAtanB=√3(tanA+tanB)
tanAtanB=1−√3(tanA+tanB)
So, tanAtanB is maximum when tanA+tanB is minimum.
And this is only possible when tanA=tanB=π12
Hence,
max(tanAtanB)=tan2π12=(2−√3)2=7−4√3
Reason is true
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion.