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Question

Assertion (A): Number of terms in the expansion of (x+y+z)5 is 21
Reason (R): The number of terms in the expansion of (x+y+z)n is n+2C2

A
Both A and R are true and R is the correct explanation of A
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B
Both A and R are true, but R is not the correct explanation of A
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C
A is true, but R is false
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D
A is false, but R is true
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Solution

The correct option is D Both A and R are true and R is the correct explanation of A
We can consider it as a distribution of n things among three in which each can get any number of things including 0 and all.
so it will have a solution as
n+31C31=n+2Cr
And for n=5
It will be 5+31C31=7C2 =21

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