wiz-icon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

Assertion (A) : Number of the disimilar terms in the sum of expansion (x+a)102+(x−a)102 is 206

Reason (R) : Number of terms in the expansion of (x+b)n is n + 1




A
Both A and R are individually true and R is the correct explanation of A.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Both A and R are individually true and R is not correct explanation of A.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
A is true but R is false
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
A is false but R is true
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D A is false but R is true
(x+a)102+(xa)102
Since a is constant let a=1
Therefore the above question can be re-written as
(1+x)102+(1x)102
=[1+102C1x1+102C2x2...+102C102x102]+[1102C1x1+102C2x2102C3x3...+102C102x102]
=2[1+102C2x2+102C2x4...+102C102x102] ...(i)
Hence number of dissimilar terms in Eq(i) will be 1022+1
=52 terms.
Hence A is false.
Reason is true.
Hence option D is the correct option.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Binomial Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon