Assertion (A) : Number of the disimilar terms in the sum of expansion (x+a)102+(x−a)102 is 206
Reason (R) : Number of terms in the expansion of (x+b)n is n + 1
A
Both A and R are individually true and R is the correct explanation of A.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Both A and R are individually true and R is not correct explanation of A.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
A is true but R is false
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
A is false but R is true
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D A is false but R is true (x+a)102+(x−a)102 Since a is constant let a=1 Therefore the above question can be re-written as (1+x)102+(1−x)102 =[1+102C1x1+102C2x2...+102C102x102]+[1−102C1x1+102C2x2−102C3x3...+102C102x102] =2[1+102C2x2+102C2x4...+102C102x102] ...(i) Hence number of dissimilar terms in Eq(i) will be 1022+1 =52 terms. Hence A is false. Reason is true. Hence option D is the correct option.