Assertion :(A) : The number of real solutions of the equation sinx=2x+2−x is zero Reason: (R) : Since |sinx|≤1
A
Both (A) and (R) are individually true and (R) is the correct explanation of (A)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(R) is not the correct explanation of (A)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(A) is true but (R) is false
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(A) is false but (R) is true
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A Both (A) and (R) are individually true and (R) is the correct explanation of (A) We know, −1≤sinx≤1⇒|sinx|≤1 Now for sinx=2x+2−x LHS=−1≤sinx≤1RHS=min(2x+2−x)=2 Hence no solution