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Question

Assertion (A) : The third term in the expansion of (2x+1x2)m does not contain x. The value of x for which that term equal to the second term in the expansion of (1+x3)30 is 4
Reason (R) : (a+x)n=nr=0Cranrxr

A
Both A and R are individually true and R is the correct explanation of A.
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B
Both A and R are individually true and R is not correct explanation of A.
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C
A is true but R is false
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D
A is false but R is true
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Solution

The correct option is C A is false but R is true
It is given that the third term is independent of x.
Therefore
T3=mC22m2xm3r
Hence m3r=0
m6=0
m=6
T2=6C2262
=23(30)= second term in (1+x3)30
T2=30C1x3
Hence
30C1x3=23(30)
30x3=30(8)
x3=8
x=2
Hence A is false.

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