Assertion (A) : The third term in the expansion of (2x+1x2)m does not contain x. The value of x for which that term equal to the second term in the expansion of (1+x3)30 is 4 Reason (R) : (a+x)n=n∑r=0Cran−rxr
A
Both A and R are individually true and R is the correct explanation of A.
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B
Both A and R are individually true and R is not correct explanation of A.
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C
A is true but R is false
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D
A is false but R is true
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Solution
The correct option is C A is false but R is true It is given that the third term is independent of x. Therefore T3=mC22m−2xm−3r Hence m−3r=0 m−6=0 m=6 T2=6C226−2 =23(30)= second term in (1+x3)30 T2=30C1x3 Hence 30C1x3=23(30) 30x3=30(8) x3=8 x=2 Hence A is false.