Assertion :All the S atoms in S4O2−6 have oxidation number equal to +2.5. Reason: Average oxidation number of sulphur in S4O2−6 is +2.5.
A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Assertion is incorrect but Reason is correct
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Solution
The correct option is D Assertion is incorrect but Reason is correct Let x be the oxidation number of S in S4O−26 . The oxidation number of oxygen is −2. The sum of the oxidation numbers is equal to the charge i.e. −2. 4x+6(−2)=−2 or, x=−2.5. Thus, the average oxidation number of sulfur is 2.5. Out of four S atoms, two S atoms are linked to other S atoms only. These two S atoms have an oxidation number of 0. The other two sulphur atoms are linked to O and S atoms. They have oxidation number of +5 each. The structure is given below: