Dear student
Assertion is true(since aryl iodides can be prepared by this method) but the reason is false. Since HI produced is oxidised back to iodine.
During the electrophilic substitution of aromatic hydrocarbon, HI is produced during the reaction.Since it is a good reducing agent, it reduces the aryl iodide back to the aromatic hydrocarbon and iodine i.e the reaction is reversible.Therefore, oxidising agents such as HNO3, HgO etc. are used to remove HI produced in the reaction as follows:
4HI + 2 HNO3→ 2N2O3 + 3H2O + 2I2
Regards