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Byju's Answer

Standard XII

Chemistry

Sulphuric Acid

Assertion :As...

Question

Assertion :Assertion : Liquids $I F_{5}$ conducts electricity Reason: Reason : Liquid $I F_{5}$ self ionizes as, $2 I F_{5} ⇌ I F_{4}^{+} + I F_{6}^{-}$

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is correct but Reason is incorrect

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Both Assertion and Reason are incorrect

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Solution

The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
Liquids $I F_{5}$ conducts electricity
Because it conduct electricity and undergoes self ionization.
Liquid $I F_{5}$ self ionizes as, $2 I F_{5} ⇌ I F_{4}^{+} + I F_{6}^{+}$ .
Hence option A is correct.

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ASSERTION: n-Pentane and n-Hexane belong to a homologous series.

REASON: n-Pentane and n-Hexane belong to the same class of hydrocarbons and they differ by a - $C H_{2}$ - group.

Assertion (A) Rate constant determined from Arrhenius equation are fairly accurate for simple as well as complex molecules.

Reason (R) Reactant molecules undergo chemical change irrespective of their orientation during collision.

(a) Both assertion and reason are correct and the reason is correct explanation of assertion
(b) Both assertion and reason are correct, but reason does not explain assertion.
(c) Assertion is correct, but reason is incorrect
(d) Both assertion and reason are incorrect
(e) Assertion is incorrect but reason is correct.

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Assertion :Assertion : Liquids IF5 conducts electricity Reason: Reason : Liquid IF5 self ionizes as,2IF5⇌IF+4+IF−6

The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for AssertionLiquids IF5 conducts electricityBecause it conduct electricity and undergoes self ionization.Liquid IF5 self ionizes as,2IF5⇌IF+4+IF+6.Hence option A is correct.

Assertion :Assertion : Liquids $I F_{5}$ conducts electricity Reason: Reason : Liquid $I F_{5}$ self ionizes as, $2 I F_{5} ⇌ I F_{4}^{+} + I F_{6}^{-}$