Assertion :Bond angle of PF3>PCl3 but bond angle of PCl3<PBr3 Reason: The bond angles show an increase on decreasing electronegativity of attached other atom on central atom but in PF3pπ−dπ bonding results in an increase in bond angle.
A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Assertion is incorrect but Reason is correct
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Solution
The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion There are two types of electron repulsions that shape these molecules: 1. lone pair-bond pair which decreases the angle 2. bond pair-bond pair which increases the angle
The lone pair-bond pair repulsion increases slowly with the decrease in electronegativity of the bonded element so fluorine will have large bond angle due to lp-bp repulsion.
But the bond pair-bond pair repulsion increases by the increase in size of the bounded element (bigger atom means bigger electron density around it). The bond pair-bond pair repulsion increases more than the lone pair-bond pair repulsion when going down a group. so due to bp-bp the bromine bond angle will be more than chlorine.