CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Assertion :Circles x2+y2=4 and x2+y28x+7=0 intersect each other at two distinct points because Reason: Circles with centres C1 and C2 and radii r1 and r2 intersect at two distance points, if |C1C2|<r1+r2

A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Assertion is correct but Reason is incorrect
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Both Assertion and Reason are incorrect
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Assertion is correct but Reason is incorrect
circles intersect at two distinct points when |r1r2|<C1C2<|r1+r2| ...(1)
now, C1(0,0) and r1=2
and C1(4,0) and r1=3
C1C2=4, |r1r2|=1 and |r1+r2|=5
condition 1 is satisfied
Therefore, they intersect in two distinct points
Ans: C

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Tangent Circles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon