Assertion :consider Δ ABC whose verticies are A = (3 + 4 cos Θ,−5+4sinΘ)
B=(3+4cos(Θ+2π3),−5+4sin(Θ+2π3))
C=(3+4cos(Θ+4π3),−5+4sin(Θ+4π3))
The orthocentre of the triangle is (3, 5) Reason: consider Δ ABC whose verticies are A = (3 + 4 cos Θ,−5+4sinΘ)
B=(3+4cos(Θ+2π3),−5+4sin(Θ+2π3))
C=(3+4cos(Θ+4π3),−5+4sin(Θ+4π3))
The triangle ABC is equilateral