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Question

Assertion :Consider the three planes P1:x−y+z=1 P2:x+y−z=1 P3:x−3y+3z=1 Let L1,L2 and L3 be the lines of intersection of the planes P1P2 and P2P3 and P1P3 respectively.


At least two of the lines and are non-parallel
Reason: The three planes do not have a common point.

A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Assertion is incorrect but Reason is correct
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Solution

The correct option is D Assertion is incorrect but Reason is correct
Given three planes are
P1:xy+z=1 ...(i)
P2:x+yz=1 ...(ii)
and P3:x3y+3z=2 ...(iii)
Solving Eqs.(I) and (ii), we have
x=0,z=1+y
which does not satisfy Eq.(iii)
As, x3y+3z=03y+3(1+y)=3(2)
Therefore Statement II is true.
Since we know that direction ratio's of line of intersection of planes
a1x+b1y+c1z+d1=0
and a2x+b2y+c2z+d2=0
b1c2b2c1,c1a2a1c2,a1b2a2b1
Using above result ,
Direction ratio's of lines L1,L2 and L3are 0,2,2,;0,4,4;0,2,2 respectively.
All the three lines L1,L2 and L3 are parallel pairwise
Statement I is false

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