Assertion :Copper (II) iodide is unstable even at ordinary temperature. Reason: The Cu2+ ion with a 17-electron outer-shell and a comparatively small radius (0.08 nm) has a strong polarising power, while the iodide ion with a larger radius (r = 0.22 nm) has a high polarisability. Hence, the polarisation of the I− by the Cu2+ leads to the complete transition of an electron from the anion to the cation. The Cu2+ ion is thus reduced to Cu ion and I− is oxidised to free iodine. The compound CuI2 therefore, does not exist.
2CuI2⟶2CuI+I2
2I−⟶I2+2e−
Cu2++2e−⟶Cu