Analysing the assertion and reason:
The half -cell reactions are:
Cu2++2e−→Cu(s);E∘=0.34V
Zn2++2e−→Zn(s);E∘=0.76V
The overall reaction is:
Cu2++Zn(S)→Cu(S)+Zn2+
E∘cell=E∘cathodeE∘anode
E∘=0.34V−(−0.76V)=+1.1V
We know that G∘=−nFE∘.
Here, E∘ is postive. So, the value of G∘ will be negative , which means that the reaction is feasible.
Copper (Cu2+) sulphate can not be stored in zinc vessels as zinc is more reactive than copper. Zinc is a stronger reducing agent than copper. Thus, zinc donates electrons to (Cu2+), and the above redox reaction occurs.
Hence, both the assertion and the reason are false.
So, option (D) is the correct answer.