Assertion : $C u^{+}$ ion is unstable in aqueous solution, whereas $F e^{2 +}$ ion is stable. Reason: $C u^{+}$ disproportionate in aqueous solution.

Statement -1 is true, statement-2 is true; statement-2 is a correct explanation for statement-1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Statement -1 is true, statement -2 is true; statement-2 is NOT a correct explanation for statement-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Statement-1 is true, statement -2 is false

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Statement -1 is false, statement -2 is true

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Statement -1 is true, statement-2 is true; statement-2 is a correct explanation for statement-1
Cu(I) ion oxidizes and reduces simultaneously in aqueous solution to give Cu(II) and Cu ions. Therefore Cu(I) complexes are generally unstable in aqueous media and tend to disproportionate. For instance, the disproportionation of non-complexed Cu(I) in water is characterized by an equilibrium constant as large as $K_{d i s p} = 10^{6}$ .

Suggest Corrections

Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

n \geq 2,

\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + . . . + \frac{1}{\sqrt{n}} > \sqrt{n}

\sqrt{n (n + 1)} < n + 1

N H_{3}

P H_{3}

N H_{3}

Join BYJU'S Learning Program