Question

Assertion: $Cu$ is stronger reducing agent than $H_2$.
Reason: $E^0$ of $C{u}^{2+}|Cu$ is negative.

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Answer 1

The standard reduction potential of the $H^{+}|H_2$ couple is fixed as zero.
Positive $E^0$ means that the redox couple is a weaker reducing agent and stronger oxidising agent than the $H^{+}|H_2$ couple.
$E^0$ of $C{u}^{2+}|Cu$ is $+0.34V$.
Here, $C{u}^{2+}$is strong oxidising agent and thus $Cu$ is a weak reducing agent.

Hence, option (d) is correct.