Assertion :Derivative of (px+q)(rx+s) is ps+qrx2 Reason: ddx(uv)=u′v+uv′ where u and v are two distinct functions.
A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Assertion is incorrect but Reason is correct
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Solution
The correct option is D Assertion is incorrect but Reason is correct Let f(x)=(px+q)(rx+s) We have, d(uv)dx=u′v+uv′ ∴f′(x)=[ddx(px+q)](rx+s)+(px+q)ddx(rx+s) =p(rx+s)+(px+q)(−rx2) =prx+ps−prx−qrx2=ps−qrx2
Hence, assertion is incorrect but reason is correct.