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Question

# Assertion :f is even, g is odd then fg(g≠0) is an odd function. Reason: If f(−x)=−f(x) for every x of its domain then f(x) is called odd function and if f(−x)=f(x) for every x of its domain, then f(x) is called even function.

A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Both Assertion and Reason are incorrect
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Solution

## The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for AssertionLet h(x)=f(x)g(x),(g(x)≠0)⇒h(−x)=f(−x)g−(x)=f(x)−g(x)=−h(x)Assertion (A) & Reason (R) both are independently true & Reason (R) is the correct explanation of Assertion (A).

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